What will be the electric field at O if the charge from one of the corners say A is removed?

What will be the electric field at O if the charge q at A is replaced by Q?

If the charge q at A is replaced by -q, it is equivalent to adding charge -2q at A. Therefore, electric field at O, E2=2q4πε0r2 along OA.

How would your answer to A be affected if Pentagon is replaced by N sided regular polygon with charge q at each of its corners?

b) If pentagon is replaced by a polygon and charge Q at each corner, then also they all will cancel out each other, and the net electric field at O will be zero.

What is the electric field at the position of the charge?

The electric field at the location of the point charge is defined as the force F divided by the charge q: Figure 23.1. Electric force between two electric charges. The definition of the electric field shows that the electric field is a vector field: the electric field at each point has a magnitude and a direction.

What will be the electric field at O if the charge from one of the corners is removed?

If the charged particle at A is removed, then the net electric field intensity at point O will be directed from point O towards point A with the same magnitude as due to the particle at point A. Hence the electric field intensity at the centre becomes q4πε0r2 from point O towards point A.

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What is the electric field at the location of Q1 due to Q2?

The electric field at the location of Q1, due to Q2 is (2.813 × 104 N/C)y.