**Contents**show

## What is the electric flux through the surface of the box?

– The net electric flux through the surface of a box is **directly proportional to the magnitude of the net charge enclosed by the box**. →net flux constant. -The net electric flux due to a point charge inside a box is independent of box’s size, only depends on net amount of charge enclosed.

## How do you find electric flux through A square?

We can calculate the flux through the square by **dividing up the square into thin strips of length L in the y direction and infinitesimal width dx in the x direction**, as illustrated in Figure 17.1.

## What is the flux through one face of the cube?

Gauss’s law tells that the total flux through an area enclosing a charge Q is Qε0. Now as the cube is having six faces and as we can assume a symmetrical distribution of fluxes among its faces, the flux associated with one of its faces is **Q6ε0**.

## How is electric flux calculated?

Electric flux is the rate of flow of the electric field through a given area (see ). … For a non-uniform electric field, the electric flux dΦE through a small surface area dS is given by **dΦE=E⋅dS d Φ E = E ⋅ d S** (the electric field, E, multiplied by the component of area perpendicular to the field).

## How do you solve electric flux?

Solution: electric flux is defined as the amount of electric field passing through a surface of area A with formula Φ e **=** E ⃗ ⋅ A ⃗ = E A cos θ Phi_e=vec{E} cdot vec{A}=E,A,costheta Φe=E ⋅A =EAcosθ where dot ( ⋅) is the dot product between electric field and area vector and θ is the angle between E and the …

## What is the flux through a cube of side A If a point charge of Q is at one of its corner?

If the charge ‘q ‘is placed at one of the corners of the cube, it will be divided into 8 such cubes. Therefore, electric flux through the one cube is **the eighth part of [dfrac{q}**{{{varepsilon _circ }}}].

## How would you compute for the flux on one side of a cube?

The flux through the surface of this cube is just **q/ϵ0 by Gauss’s Law** since it is a closed surface containing the charge. Now imagine dividing each face of this larger cube into four squares of side length ℓ.

## What is the electric field of a cube?

The electric field is **zero everywhere inside the central cubic region** since the electric fields of opposing planes cancel exactly at any interior point.